TITLE: How many isolated roots can a polynomial in $z$ and $\overline{z}$ have?
QUESTION [11 upvotes]: This is probably well-known by I can't find it now online. My guess is that if the degree is $n$ then it's $2n$ but it's just a hunch.
EDIT:
This is an edited version. Before I asked about roots without qualification.

REPLY [12 votes]: Alexandre Eremenko already described the failure of the $2n$ bound, but I thought I'd illustrate with an example.  I did an unstructured manual search on cubic polynomials, and here's an example with 8 zeroes: $2z^3 + 4\bar{z}^3 - z^2 + z\bar{z} - \bar{z}^2 + z + 0.1 + 0.1i =0$.  The graph shows vanishing loci of the real and imaginary parts, and the $Im(P(z,\bar{z}))=0$ locus is made of the components that are asymptotic to the $x$ and $y$ axes together with the lower right bubble.