TITLE: Are all transversely oriented, transversely measured foliations given by closed forms?
QUESTION [6 upvotes]: This paper, "AF-algebras and topology of 3-manifolds" seems to claim on page 5 that a [transversely] oriented measured foliation on a compact surface is given by a closed form. On the other hand, the book "Differential Geometry of Foliations: The Fundamental Integrability Problem" by Reinhart places a restriction on the transversely oriented foliation to have trivial holonomy. On the other hand, the latter result pertains to $C^k$-foliations, while the first one refers to the smooth case.
Is the claim in the paper false?
EDIT: "Smooth" is a bit of misnomer. What I had in mind is foliations suited to  train tracks (so the singular leaves only have cusps as singularities.)

REPLY [2 votes]: The claim is true and you find it on page 319 of Farb-Margalit's book.
The point is that the transition maps between foliation charts (with the leaves as y-level sets) are of the form $(x,y)\to (f(x,y),\pm y+c)$. (This is because the transverse measure has to be preserved. So the transverse measure seems essential for the claim to be true.)
Clearly $dy$ or $-dy$ define the singular foliation in a chart, and by coorientability of the foliation you can then consistently choose one of the two for each chart.