TITLE: vector bundles associated to a covering space
QUESTION [7 upvotes]: Let $M$ be a $m$-dimensional manifold whose cohomology ring and cell structure are well-understood, such that there is a free action of the symmetric group $S_n$ on $M$. Then we have a $n!$-sheeted covering space
$$
\pi:M\to M/S_n.
$$
Let $S_n$ act on the Euclidean spaces $\mathbb{R}^n$ and $\mathbb{C}^n$ by permuting the order of coordinates.
We obtain vector bundles by attaching Euclidean spaces as fibres to the covering $\pi$:
$$
\xi:\mathbb{R}^n\to M\times_{S_n}\mathbb{R}^n\to M/S_n,
$$
$$
\xi^\mathbb{C}: \mathbb{C}^n\to M\times_{S_n}\mathbb{C}^n\to M/S_n.
$$
Question: (1). Any  methods to know the Stiefel-Whitney classes $$
w(\xi)?
$$
Question: (2). Any  methods to know the Chern classes $$
c(\xi^\mathbb{C})?
$$
Note: if we take coefficients to be $\mathbb{Q}$, then all the Chern class vanish. Hence we take the coefficients to be $\mathbb{Z}/p$ for $p$ prime.

REPLY [11 votes]: When you have an Euclidean vector space of type:
$$\mathbb{R}^n\rightarrow M\times_{S_n}\mathbb{R}^n\rightarrow M/S_n$$
Then its classifying map $\phi:M/S_n\rightarrow BO(n)$ factors as:
$$M/S_n\rightarrow BS_n\stackrel{\rho_n}{\rightarrow} BO(n)$$
where $\rho_n$ is induced by the regular reprsentation $S_n\rightarrow O(n)$.
Thus what you want to compute is the morphism 
$$\rho_n^*:H^*(BO(n),\mathbb{F}_2)\rightarrow H^*(BS_n,\mathbb{F}_2)$$
A nice way to formulate such a result is to put all $n$ together. Then you have a map of Hopf rings 
$$\rho:H^*(BO(\bullet),\mathbb{F}_2)\rightarrow H^*(BS_{\bullet},\mathbb{F}_2).$$
Then set $w_{i,n}=\rho^*_n(w_i)\in H^i(BS_n,\mathbb{F}_2)$ where $w_i$ is the i-th Stiefel-whitney class and $w(k,l)=w_{2^k(2^l-1),2^{k+l}}$. Then Giusti, Salvatore and Sinha proved in their paper "Mod-2 cohomology of symmetric groups as a Hopf ring" (theorem $10.7$):
"The classes $w(k,l)$ generate $H^*(BS_{\bullet},\mathbb{F}_2)$ as a Hopf ring."