TITLE: A sum over characters of $S_{2n}$ and zonal spherical functions of $(S_{2n},H_n)$
QUESTION [6 upvotes]: The hyperoctahedral group $H_n$ can be seen as the centralizer of the permutation $(12)(34)\cdots (2n-1\,2n)$ in $S_{2n}$.  It has $2^nn!$ elements.
The quantities $$ \omega_\lambda(\pi)=\frac{1}{2^nn!}\sum_{h\in H_n}\chi_{2\lambda}(h\pi)$$ are called the zonal spherical functions of the Gelfand pair $(S_{2n},H_n)$. Here $2\lambda=(2\lambda_1,2\lambda_2,...)$ and $\chi$ are irreducible characters of $S$.
I have observed the following very nice result:
$$ \frac{2^nn!}{(2n)!}\sum_{\lambda\vdash n}\chi_{2\lambda}(1^{2n})\omega_\lambda(\pi)=\begin{cases} 1, &\pi\in H_n\\0, &\pi\notin H_n\end{cases}$$
Does anyone know how to prove this? (Orthogonality of characters is not straightforwardly useful) If so, can it be generalized to $\sum_{\lambda\vdash n}\chi_{2\lambda}(\mu)\omega_\lambda(\pi)$?

REPLY [8 votes]: The essential thing here is that the characters $\chi_{2\lambda}$ are exactly the irreducible constituents of the induced character $(1_{H_n})^{S_n}$. The result generalizes to an arbitrary subgroup $H\leq G$ of a finite group $G$ as follows: For $x$, $y\in G$, we have $\DeclareMathOperator{\Irr}{Irr}$
$$ \frac{ |H| }{ |G| } 
   \sum_{ \chi\in \Irr(G \mid 1_H) }
   \chi(x^{-1} ) \omega_{\chi}(y) 
   = \frac{ |x^G \cap Hy| }{ |x^G| }.  \tag{*}
$$
Here $\Irr(G \mid 1_H)$ denotes the set of irreducible constituents of $(1_H)^G$, which by Frobenius reciprocity is the set of $\chi\in \Irr(G)$ such that $1_H$ is a constituent of the restriction $\chi_H$.
As above, 
$$ \omega_{\chi}(y) = \frac{1}{|H|}
                      \sum_{h\in H} \chi(hy),
$$ 
but we do not have to assume that $(G,H)$ is a Gelfand pair. ($x=1$ and $y=\pi$ is your result.) 
Proof: Let
$$ e_H = \frac{1}{|H|} \sum_{h\in H} h \in \mathbb{C} H,  
$$
the central primitive idempotent of the group algebra belonging to $1_H$. Then $\omega_{\chi}(g) = \chi(e_H g)$ by defintion. 
If $1_H$ is not a constituent of the restriction $\chi_H$ for $\chi\in \Irr(G)$, then $\chi(e_Hg) = 0$ for all $g\in G$. 
Thus we can let run $\chi$ over all of $\Irr(G)$ in the sum in (*). 
We get
$$ \frac{ |H| }{ |G| } 
     \sum_{ \chi\in \Irr G } \chi( x^{-1} ) \omega_{\chi}(y)
   = \frac{ 1 }{ |G| } 
     \sum_{ h\in H } \sum_{ \chi\in \Irr G } 
                     \chi(x^{-1})\chi(hy), 
$$
and the second orthogonality relation for characters yields the result.