TITLE: $\log \log p / \log \log n$, where $p|n$, gets equidistributed in [0,1] (for almost all $n$)
QUESTION [7 upvotes]: According to Hardy-Ramanujan/Erdős-Kac we know that usually there are $\sim\log\log n$ prime numbers in a factorization. But if you pick up a natural number at random, and you factor it, what is the expected distribution of its factors?
By the Turán–Kubilius inquality, we see that this is the expectation:
$$ \left\{\frac{\log \log p}{\log \log n}:\ p\mid n\right\}$$
tend to equidistribute on $[0,1]$. 
Where can I find a more precise statement of the above? 
[Edit: a previous version contained comments irrelevant to the question]

REPLY [12 votes]: For precise information on many questions of this type you should consult the Cambridge Tract, Divisors by Hall and Tenenbaum.  Here is Hildebrand's review in the Bulletin of this book.  A much more precise version of your question is a result of Erdős.  Suppose $n =p_1^{\alpha_1} \cdots p_k^{\alpha_k}$ is the prime factorization of $n$ with $p_1 < p_2 < \ldots <p_k$.  Thus for almost all $n$, Hardy-Ramanujan tells us that $k=\omega(n) \sim \log \log n$.  Let $\xi(n)$ be any function tending to infinity with $n$.  For almost all $n$, Erdős showed that
$$ 
|\log \log p_i - i| \le (1+\epsilon) \sqrt{2i \log \log i}
$$ 
holds for all $\xi(n)\le i \le k$; see (3) of Hildebrand's review.  There has been more recent progress in the field, but Divisors is still a good place to start.