TITLE: Simply generated sequences with mysterious differences
QUESTION [5 upvotes]: Suppose that $a_0 < a_1,$ $b_0 < b_1,$ and $$a_n=a_1b_{n-1}+a_0b_{n-2}+qn+r$$ for $n \geq 2$, where $a_0,a_1,b_0,b_1,q,r$ are integers such that $(a_n)$ and $(b_n)$ are increasing and ${(|a_n|)}$ and ${(|b_n|)}$ partition the positive integers. What can be proved about the cardinality of $$D=\{(a_n-a_{n-1},b_n-b_{n-1})\},$$ for $n \geq 0?$
Experimental results:

If $(a_0,a_1,b_0,b_1,q,r)=(-1,2,3,4,2,0)$, then $|D|=9$; see "Experimental fact" at A possibly surprising appearance of $\sqrt{2}.$ 
If $(a_0,a_1,b_0,b_1,q,r)=(1,2,3,4,1,0)$, then $D=\{(1,1),(4,1),(4,2),(5,1),(6,1),(11,1)\}.$  
If $(a_0,a_1,b_0,b_1,q,r)=(3,4,1,2,1,-7)$, then $D=\{(1,1),(2,3),(8,1),(8,2),(11,1),(12,1),(16,2),(18,1)\}.$

Reasons for studying the set $D$ include these related questions:

Is $(a_n-a_{n-1})$ ever linearly recurrent?
Let $d$ be a number that occurs infinitely many times in $(b_n-b_{n-1})$, and let $(p_n)$ be the sequence of numbers $k$ such that $b_k-b_{k-1}=d.$ Must $(p_n/n)$ converge? As an example, for $(a_0,a_1,b_0,b_1,q,r)=(-1,2,3,4,2,0)$, we have 
$$(p_n) = (1,11,13,16,19,22,25,28,31,34,37,43,45,51,53,56,62,\dots),$$
and it appears that $\lim_{n \to \infty} p_n/n = 1+\sqrt{2}.$

REPLY [4 votes]: This is less more than a long comment. It seems that a somehow simpler case is the  when $a_{n+1}-a_n>1$ (at least eventually) which means $b_{n+1}-b_n\in\{1,2\}$ (eventually), and  $a_{n+1}-a_n$ takes values in a finite set $\mathcal{A}$ of say $r$ integers greater or equal to $2$. Then the sequence  $a_{n+1}-a_n$ is generated by a substitution map (like in the one described here or here, so that the entire sequence $a_{n+1}-a_n$, seen as an infinite string, has the form $p\cdot\tau(p)\cdot\tau(p)^2\cdot\tau(p)^3\dots$, where the dots stand  for concatenation of words, and $p$ is a prefix. For such a substitution map $\tau$  one can write an associated $r\times r$ transition matrix $A:=(a_{ij})$ for the number of occurrences of each symbol in a transformed word: let $a_{ij}$ denote the number of  occurrences of the letter $s_i$ in the word $\tau(s_j)$. Then, if in the vector $X$, $X_i$ is the number of occurrences of  $s_i$ in a given word $w$,  the coordinates of $AX$ give the number of occurrences of each $s_i$ in the word $\tau(w)$, so that, for $w=p$, the vector $A^k X$ gives the distribution of letters in $\tau(p^k)$; the length of  $\tau(p^k)$ is the sum of coordinates of $A^{k-1} X$. This way the various asymptotics of $a_n$ can be easily related to the spectrum of $A$; in fact one use the standard techniques of  finite Markov chains introducing a suitable Markov chain deduced from the map $\tau$. For instance, both quoted cases can be treated this way.
The case when $a_{n+1}-a_n$ can take the value $1$ frequently, so that $b_{n+1}-b_n$ assumes more values, seems less clear to me, but it may possibly be studied in the same lines.