TITLE: The ¨irreducible¨ representation variety of surface group
QUESTION [5 upvotes]: Let $S$ be a closed surface of genus larger than 1, $G$ be a compact, simply connected simple Lie group with finite center. 
Consider the representation variety $M(S,G)=Rep(\pi_1(S), G)$. Witten´s formula gives a way to calculate the volume of this space. 
Now Let $X$ be the subset of this variety consisting of irreducible representations of the surface group $\pi_1(S)$ to $G$, and let´s call it the ¨irreducible¨ representation variety of surface group.
My questions are:

Can we say anything about the distribution of $X$?  For example, is it an open submanifold of Zariski dense part of $M(S,G)$?  And is it connected? 
Do we have some formulas, similar to Witten´s, to calculate the volume of $X$ w.r.t symplectic form that restricted from $M(S,G)$?

Answers and References are very welcome. Thanks a lot.

REPLY [2 votes]: Let $\Sigma$ be a closed orientable surface of genus $g\geq 2$, and $\pi$ its fundamental group.  Let $X(\pi, G)=Hom(\pi,G)/G$ be the conjugation quotient for $G$ a compact Lie group whose derived subgroup $DG$ is simply connected.
From:
Ho, Nan-Kuo; Liu, Chiu-Chu Melissa. Connected components of spaces of surface
group representations.II. Int. Math. Res. Not. (2005), no. 16, 959–979,
we know $X(\pi,G)$ is connected (irreducible).  Moreover, the reducible locus is a proper Zariski closed subset.
The fact that a free group of rank $g\geq 2$ surjects onto $\pi$, implies the irreducible locus is non-empty.
Thus, the locus of irreducible representations is connected, open, and dense.  
Since the reducible locus is proper and Zariski closed, any volume calculation for $X(\pi, G)$ will be the same for the irreducible locus.
However, even if $G$ is simply-connected and simple (as you postulate), the irreducible locus will generally have orbifold singularities (unless $G=SU(n)$).  So it is not a submanifold of the locus of Zariski-dense representations (those whose image is Zariski dense).