TITLE: Theorem 2.1.2.2 Higher Topos Theory
QUESTION [6 upvotes]: At the page 74 of HTT, there is the following theorem

Let $S$ be a simplicial set, $\mathcal{C}$ a simplicial category, and $\phi: \mathfrak{C}[S] \rightarrow \mathcal{C}^{op}$ a simplicial functor.  The straightening and unstraigntening functors determine a Quillen adjunction
  $$ St_{\phi} : (Set_{\Delta})_{/S} \leftrightarrows Set_{\Delta}^{\mathcal{C}}  :Un_{\phi}$$
  where $(Set_{\Delta})_{/S}$ is endowed with the contravariant model structure and $Set_{\Delta}^{\mathcal{C}}$ with the projective model structure. [...]

In then says that the proof is easy, but I can't manage to show that $St_{\phi}$ sends cofibrations to projective cofibrations. I thought that since the the class of morphisms which are sent to  projective cofibrations is weakly saturated it is enough to show the result for all inclusions $\partial \Delta^n \subseteq \Delta^n$.
I did not have much success for the simplicial category $\mathcal{C}$ and the map $\phi$ could be anything and I have a hard time dealing with it.
Furthermore there is something else which troubles me: the model structure on the $Set^{\mathcal{C}}_{\Delta}$ makes no use of the simplicial enrichement on both $\mathcal{C}$  and $sSet$ so I was wondering if I was not missing something by believing that the that model structure on $Set^{\mathcal{C}}_{\Delta}$ is really the projective model structure coming from the Kan model structure on $sSet$ and not the one coming somehow from an other model stucture using the simplicial enrichement.

REPLY [5 votes]: I think what Lurie might have meant when he wrote "It is easy to see that $St_{\phi}$ preserves cofibrations" in the proof of Theorem 2.2.1.2, is that it is easy to see it if you take into account the compatibility of straightening with left Kan extensions as described just above in Proposition 2.2.1.1. Indeed, combining (1) and (2) of the latter proposition we see that given any generating cofibration $\partial \Delta^n \to \Delta^n \to S$ in $({\rm Set}_{\Delta})_{/S}$, in order to show that $St_{\phi}(\partial \Delta^n \to \Delta^n)$ is a projective cofibration in ${\rm Set}_{\Delta}^{{\cal C}}$ it is enough to show that $St_{Id}(\partial \Delta^n \to \Delta^n)$ is a projective cofibration in ${\rm Set}_{\Delta}^{\mathfrak{C}[\Delta^n]^{op}}$. The map $St_{Id}(\partial \Delta^n \to \Delta^n)$ can then be described very explicitly, and one can check that it is a pushout of a map of the form $(i_0)_!\partial ((\Delta^1)^n) \to (i_0)_!(\Delta^1)^n$, where $(i_0)_!$ denotes the left Kan extension functor along the terminal object inclusion $\{0\} \subseteq \mathfrak{C}[\Delta^n]^{op}$ and $\partial ((\Delta^1)^n) \to (\Delta^1)^n$ is the inclusion of the boundary of the $n$-cube inside the full $n$-cube.
Edit:
In response to the comment, here are some more details on the computation. First note that by definition the map $St_{Id}(\partial \Delta^n)(0) \to St_{Id}(\Delta^n)(0)$ can be identified with the inclusion 
$$ (*)\quad {\rm Map}_{\mathfrak{C}[\partial \Delta^{n+1}]}(0,n+1) \subseteq {\rm Map}_{\mathfrak{C}[\Delta^{n+1}]}(0,n+1) = {\rm N}({\rm P}(\{1,...,n\})) \cong (\Delta^1)^n ,$$ 
where ${\rm P}(\{1,...,n\})$ is the poset of subsets of $\{1,...,n\}$ and ${\rm N}(-)$ is the nerve. Now for $i \in \{1,...,n\}$, image of $\mathfrak{C}[\Delta^{\{0,...,\hat{i},...,n+1\}}] \to \mathfrak{C}[\Delta^{n+1}]$ on the mapping space from $0$ to $n+1$ is exactly the face of ${\rm N}({\rm P}(\{1,...,n\}))$ corresponding to the subposet spanned by those subsets which do not contain $i$. On the other hand, the face of ${\rm N}({\rm P}(\{1,...,n\}))$ corresponding to the subposet spanned by those subsets which do contain $i$ is exactly the image of 
$${\rm Map}_{\mathfrak{C}[\Delta^{\{0,...,i\}}]}(0,i) \times {\rm Map}_{\mathfrak{C}[\Delta^{\{i,...,n+1\}}]}(i,n+1) \subseteq {\rm Map}_{\mathfrak{C}[\partial \Delta^{n+1}]}(0,n+1)$$ 
in ${\rm Map}_{\mathfrak{C}[\Delta^{n+1}]}(0,n+1)$. This shows that the image of (*) contains all the boundary of the cube. It is also not difficult to check that this image is contained in the boundary of the cube, and hence coincides with it.