TITLE: Are all cubic graphs almost Hamiltonian?
QUESTION [14 upvotes]: Call a graph $G$ $n$-almost-Hamiltonian if there is a closed walk in $G$ that visits every vertex of $G$ exactly $n$-times.  So a Hamiltonian graph is $n$-almost-Hamiltonian for all $n$.  Are all cubic graphs $n$-almost-Hamiltonian for some sufficiently large $n$?

REPLY [15 votes]: Yes, every connected cubic graph is 3-almost-Hamiltonian.
Replace each edge by two parallel edges then follow an Eulerian circuit.
In the case of a bridgeless cubic graph, you can add a perfect matching instead of doubling each edge, which shows they are 2-almost-Hamiltonian.