TITLE: The $K$-theory homology of the Eilenberg-MacLane spectrum
QUESTION [13 upvotes]: Let $KU$ be the complex $K$-theory spectrum and $H\mathbb{Z}$ be the Eilenberg-MacLane spectrum. 
For $n\in \mathbb{Z}$, it is known what the homology groups $KU_{n}(H\mathbb{Z})$ are?

REPLY [21 votes]: We have $KU_*(H\mathbb Z) = \pi_*(KU\wedge H\mathbb Z)$; this ring is concentrated in even dimensions and carries an isomorphism between the additive and multiplicative formal group law, hence is rational. Thus the map
$$
KU\wedge H\mathbb Z\to (KU\wedge H\mathbb Z)\wedge H\mathbb Q\cong KU\wedge H\mathbb Q
$$
is an isomorphism. The Chern character $KU\to \sum_{i\in\mathbb Z} \Sigma^{2i}H\mathbb Q$ is a rational equivalence, so that
$$
KU_{2n}(H\mathbb Z) \cong\mathbb Q, KU_{2n+1}(H\mathbb Z) \cong 0\ .
$$
Alternatively, the Snaith theorem $KU\cong \Sigma^{\infty}\mathbb{CP}^{\infty}[\beta^{-1}]$, where $\beta\in \pi_2(\mathbb{CP}^{\infty})$ is the Bott element, shows that
$$
H_*(KU)\cong H_*(\mathbb{CP}^{\infty})[\beta^{-1}]\ .
$$
It's easy to calculate that $H_*(\mathbb{CP}^{\infty})$ is a divided power algebra on the generator $\beta\in H_2(\mathbb{CP}^{\infty})$. Since $\beta^n$ is divisible by $n!$, this ring is the Laurent series over $\mathbb Q$ generated by $\beta$.

REPLY [20 votes]: Since for any two spectra $E,F$ we have
$$
E_n(F)=[\mathbb{S}^n,E\wedge F]\cong [\mathbb{S}^n,F\wedge E] = F_n(E),
$$
you may as well ask about $H_n(KU;\mathbb{Z})$, the integral homology of the complex $K$-theory spectrum.
This calculation is carried out e.g. in Chapter 16 of the book
Switzer, Robert M., Algebraic topology – homology and homotopy., Classics in Mathematics. Berlin: Springer. xii, 526 p. (2002). ZBL1003.55002.
In particular, Theorem 16.25 gives the Pontrjagin algebra structure as
$$
H_*(KU;\mathbb{Z})\cong \mathbb{Q}[u,u^{-1}],$$
the ring of finite Laurent series over $\mathbb{Q}$ in an element $u\in H_2(KU;\mathbb{Z})$.