TITLE: Why is the largest signed 32 bit integer prime?
QUESTION [5 upvotes]: This may be subjective, but does anyone have any insight into why this is the case? This struck me while considering that it's also the eigth Mersenne prime (2^31-1=2147483647). 

I'm now wondering why this might be the case.

UPDATE:
It's been pointed out that the relationship doesn't necessarily hold for larger storage classes, e.g., 2^63 - 1 is not prime.

REPLY [7 votes]: Why is $3$ prime?  I don't really know that there are meaningful answers to these kinds of questions.  The best I can think of is some reasons it is not obviously composite, e.g. since $5$ is prime $2^5 - 1 = 31$ is not obviously composite (and it turns out to be prime) hence $2^{31} - 1$ is not obviously composite.  This is two applications of the "lemma" that if $p$ is prime then $2^p - 1$ is not obviously composite.
Note that any prime factor of $2^p - 1$ has to be congruent to $1 \bmod p$ by Fermat's little theorem, so it is "easier" for such numbers to be prime.