TITLE: Nondegeneracy of kernel of map on homology induced by covering of surfaces
QUESTION [5 upvotes]: Let $f:X \rightarrow Y$ be a finite covering map between compact oriented surfaces and let $K$ be the kernel of the induced map $f_\ast: H_1(X) \rightarrow H_1(Y)$.  Here homology has rational coefficients.
Question: must $K$ be nondegenerate with respect to the symplectic algebraic intersection pairing $\omega$ on $H_1(X)$?  In other words, is it true for all nonzero $k \in K$, there exists some $k’ \in K$ with $\omega(k,k’) \neq 0$?

REPLY [7 votes]: The answer is yes. Let me work with $H^1$, which is canonically isomorphic to $H_1$ by Poincaré duality. I claim that $K=\operatorname{Ker} f_*$ is the orthogonal of $\ \operatorname{Im}f^* $: this is because  $(\beta \cdot f^*\alpha )=(f_*\beta \cdot \alpha )$ for $\alpha $ in $H^1(Y)$ and $\beta $ in $H^1(X)$.
Now for $\alpha ,\beta \in H^1(Y)$ we have $(f^*\alpha \cdot f^*\beta )=d(\alpha \cdot \beta )$, where $d$ is the degree of the covering. Thus $\ \operatorname{Im}f^* $ is a non-degenerate subspace of $H^1(X)$, hence its orthogonal $K$ is also non-degenerate.