TITLE: Question about the dimension of a Contact (Symplectic) manifold
QUESTION [5 upvotes]: I am reading about contact geometry and I have a question: Why do we only consider contact structure of an odd-dimension manifold? and the same question for definition of symplectic geometry?
I think for the contact geometry case, a reason is that we want $\alpha \wedge (d\alpha)^n$ to be a volume form. Am I right? I am not sure about that.
Thank you so much for your help.
P.S there is no tag for Contact-geometry.

REPLY [6 votes]: And by popular request, here's my comment as an answer :)
Your guess is correct. Contact structures are structures associated to a one-form $\alpha$ with maximal rank. There are two cases:

for odd rank, you want $\alpha∧(d\alpha)^k$ to be nowhere vanishing for the largest possible $k$ allowed by dimension, and
for even rank, you want the same condition on $(d\alpha)^k$.

In the former case you have a contact structure and in the latter an exact symplectic structure.
More generally, symplectic forms are nondegenerate by definition.  You can understand nondegeneracy of a 2-form $\omega$ pointwise, where it turns into the statement that an antisymmetric matrix has nonzero determinant.  This can only happen if the dimension is even.
I'm assuming finite-dimensionality throughout.  There is a reasonably well-developed theory of infinite-dimensional symplectic manifolds and presumably also of contact manifolds.