TITLE: What is the minimal degree of a smooth projective embedding of a hyperelliptic curve?
QUESTION [14 upvotes]: (partly motivated by this question, but different: Degree of a Variety)
For a hyperelliptic curve $C$ of genus $g$ (over an algebraically closed field of characteristic not two) what is the smallest $d$ for which $C$ can be embedded in some $\mathbb{P}^n$ (I guess $n=3$ wlog) as a smooth curve of degree $d$? Does it depend only on $g$? Can anything be said for an arbitrary curve?

REPLY [11 votes]: Felipe,  I believe the answer here is d=g+3.  To see that you can embed your curve in this degree is straightforward - just choose a generic line bundle of degree g+3 and it will work.
In the case of hyperelliptic curves, I don't think you can do better.  The key point is that any special linear series on a hyperelliptic curve comes from taking a multiple of the pullback of O(1) on P^1  together with some base points.  (You can find this fact in Arbarello-Cornalba-Griffiths-Harris.)  Since these cannot give rise to embeddings (either have base points or the associated map factors through the hyperelliptic involution) we conclude the the embedding line bundle has no H^1.  The Riemann-Roch gives g+3 as the lower bound for having 4 sections.

REPLY [2 votes]: I agree with Tom G in the case of hyperelliptic curves. Interestingly, I think the bound for a general curve of degree $g$ should be $d = (3/4)g+3$. More specifically, the Brill-Noether theorem tells us that, for this $d$, there is a line bundle with $\dim H^0(X, L) =4$. I would guess (but don't know a reference) that, for generic $X$, this line bundle gives an embedding $X \to \mathbb{P}^3$.