TITLE: Criteria for Positivity of Pseudoddifferential Operators on Manifolds
QUESTION [7 upvotes]: Let $(M,g)$ be a Riemannian Manifold and $L^2$ the Hilbert space given by the volume form associated to the metric.  Let $L_0^2$ be the subspace which is orthogonal to the constant functions.  When is a pseudodifferential operator on $M$ a positive operator on $L^2_0$?
For second order operators the Laplacian $\Delta$ is the main example.
For order zero, the obvious examples are multiplication by $f$ where $f \in C^\infty(M)$ is a smooth function and $f > 0$.  Conversely if $f < 0$ anywhere then it is clear that the multiplication operator is not positive.
If $A$ is positive on $L^2_0$ then
$(\Delta^{p/2} A \Delta^{p/2} v, v) = (A \Delta^{p/2} v, \Delta^{p/2} v) > 0$
for $v \in L^2_0$ non-zero.  So we can use the Laplacian as a sort of natural way to change the order of a given positive operator.  Note that the principle symbol of such an operator is $||\xi||^{p}\sigma(A)(x,\xi)$.
How else can I construct more positive pseudodifferential operators? So far I can only come up with operators whose symbols in a fiber look like $||\xi||^{p}f(x)$.  I am looking for "more interesting" symbols, such as those whose restriction to the co-sphere at a point is non-constant.
Ideally of course I would just like a global criterion for a symbol to quantize to a positive operator, but something tells me that this is a hard problem. If it is any easier, I would also be interested in specific examples, like the sphere with the round metric.

REPLY [2 votes]: Let $A$ be a selfadjoint (pseudo)differential operator of order 2 on $(M,g)$ with a nonnegative symbol. It is a consequence of the Fefferman-Phong inequality that $A$ is semi-bounded from below, i.e. $A+C\ge 0$, where $C$ is a constant.
Now you could object that the total symbol is not invariantly defined: true but considering that $A$ acts on half-densities (identified with functions on a Riemannian manifold), you get that
$$
a_2+ \Re a_1
$$
is indeed invariantly defined. Here the symbol of $A$ is
$a_2+a_1+r_0$, where $a_j$ is of order $j$, $r_0$ of order 0, $a_2\ge 0,\quad a_2+\Re a_1\ge 0$.